-[3z-(6z+1)]=1+(2z+2)

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Solution for -[3z-(6z+1)]=1+(2z+2) equation:


Simplifying
-1[3z + -1(6z + 1)] = 1 + (2z + 2)

Reorder the terms:
-1[3z + -1(1 + 6z)] = 1 + (2z + 2)
-1[3z + (1 * -1 + 6z * -1)] = 1 + (2z + 2)
-1[3z + (-1 + -6z)] = 1 + (2z + 2)

Reorder the terms:
-1[-1 + 3z + -6z] = 1 + (2z + 2)

Combine like terms: 3z + -6z = -3z
-1[-1 + -3z] = 1 + (2z + 2)
[-1 * -1 + -3z * -1] = 1 + (2z + 2)
[1 + 3z] = 1 + (2z + 2)

Reorder the terms:
1 + 3z = 1 + (2 + 2z)

Remove parenthesis around (2 + 2z)
1 + 3z = 1 + 2 + 2z

Combine like terms: 1 + 2 = 3
1 + 3z = 3 + 2z

Solving
1 + 3z = 3 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
1 + 3z + -2z = 3 + 2z + -2z

Combine like terms: 3z + -2z = 1z
1 + 1z = 3 + 2z + -2z

Combine like terms: 2z + -2z = 0
1 + 1z = 3 + 0
1 + 1z = 3

Add '-1' to each side of the equation.
1 + -1 + 1z = 3 + -1

Combine like terms: 1 + -1 = 0
0 + 1z = 3 + -1
1z = 3 + -1

Combine like terms: 3 + -1 = 2
1z = 2

Divide each side by '1'.
z = 2

Simplifying
z = 2

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